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Tadej Pogacar domina Giro d'Italia 2024, conquista sexta etapa y amplía su ventaja en la clasificación general

Tadej Pogacar ha vuelto 5️⃣ a demostrar su dominio absoluto en el Giro d'Italia de este año, ganando en solitario la etapa 20, su sexta 5️⃣ victoria de etapa, aumentando así su ventaja en la clasificación general antes de la última jornada.

Pogacar pudo hacer gestos a 5️⃣ la multitud en los metros finales de la ruta de 184 km desde Alpago hasta Bassano del Grappa, ya que 5️⃣ el ciclista del UAE Team Emirates llegó en solitario con una ventaja de aproximadamente 10 minutos sobre sus rivales más 5️⃣ directos en la clasificación general.

El esloveno ya tenía una ventaja general de 7min 42seg sobre Daniel Felipe Martínez de Bora-Hansgrohe, 5️⃣ y cuando atacó en la segunda subida del día al Monte Grappa, nadie pudo seguir su ritmo.

Valentin Paret-Peintre (Decathlon-AG2R La 5️⃣ Mondiale), ganador de la etapa 10, llegó en segundo lugar, ya que superó a Martínez, que finalizó tercero, más de 5️⃣ dos minutos por detrás de Pogacar. El galés Geraint Thomas, del Ineos Grenadiers, finalizó con el mismo tiempo que Martínez 5️⃣ y sigue tercero en la general.

Solo queda la llegada triunfal a Roma.

Más información seguirá

Clasificación de la etapa 20

Posición Ciclista Equipo Tiempo
1 Tadej Pogacar UAE Team 5️⃣ Emirates 4h 22' 15"
2 Valentin Paret-Peintre Decathlon-AG2R La Mondiale 4h 24' 22"
3 Daniel Felipe Martínez Bora-Hansgrohe 4h 26' 36"

Clasificación general

  1. Tadej Pogacar (UAE Team Emirates) - 86h 22' 5️⃣ 18"
  2. Daniel Felipe Martínez (Bora-Hansgrohe) - a 6' 19"
  3. Geraint Thomas (Ineos Grenadiers) - a 7' 24"
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    A gambling strategy where the amount is raised until a person wins or becomes

    insolvent

    A martingale is a class of ♠ betting strategies that originated from and were

    popular in 18th-century France. The simplest of these strategies was designed for a

    ♠ game in which the gambler wins the stake if a coin comes up heads and loses if it comes

    up ♠ tails. The strategy had the gambler double the bet after every loss, so that the

    first win would recover all ♠ previous losses plus win a profit equal to the original

    stake. Thus the strategy is an instantiation of the St. ♠ Petersburg paradox.

    Since a

    gambler will almost surely eventually flip heads, the martingale betting strategy is

    certain to make money for ♠ the gambler provided they have infinite wealth and there is

    no limit on money earned in a single bet. However, ♠ no gambler has infinite wealth, and

    the exponential growth of the bets can bankrupt unlucky gamblers who choose to use ♠ the

    martingale, causing a catastrophic loss. Despite the fact that the gambler usually wins

    a small net reward, thus appearing ♠ to have a sound strategy, the gambler's expected

    value remains zero because the small probability that the gambler will suffer ♠ a

    catastrophic loss exactly balances with the expected gain. In a casino, the expected

    value is negative, due to the ♠ house's edge. Additionally, as the likelihood of a string

    of consecutive losses is higher than common intuition suggests, martingale strategies

    ♠ can bankrupt a gambler quickly.

    The martingale strategy has also been applied to

    roulette, as the probability of hitting either red ♠ or black is close to 50%.

    Intuitive

    analysis [ edit ]

    The fundamental reason why all martingale-type betting systems fail

    is that ♠ no amount of information about the results of past bets can be used to predict

    the results of a future ♠ bet with accuracy better than chance. In mathematical

    terminology, this corresponds to the assumption that the win–loss outcomes of each ♠ bet

    are independent and identically distributed random variables, an assumption which is

    valid in many realistic situations. It follows from ♠ this assumption that the expected

    value of a series of bets is equal to the sum, over all bets that ♠ could potentially

    occur in the series, of the expected value of a potential bet times the probability

    that the player ♠ will make that bet. In most casino games, the expected value of any

    individual bet is negative, so the sum ♠ of many negative numbers will also always be

    negative.

    The martingale strategy fails even with unbounded stopping time, as long as

    ♠ there is a limit on earnings or on the bets (which is also true in practice).[1] It is

    only with ♠ unbounded wealth, bets and time that it could be argued that the martingale

    becomes a winning strategy.

    Mathematical analysis [ edit ♠ ]

    The impossibility of winning

    over the long run, given a limit of the size of bets or a limit in ♠ the size of one's

    bankroll or line of credit, is proven by the optional stopping theorem.[1]

    However,

    without these limits, the ♠ martingale betting strategy is certain to make money for the

    gambler because the chance of at least one coin flip ♠ coming up heads approaches one as

    the number of coin flips approaches infinity.

    Mathematical analysis of a single round [

    edit ♠ ]

    Let one round be defined as a sequence of consecutive losses followed by either

    a win, or bankruptcy of the ♠ gambler. After a win, the gambler "resets" and is

    considered to have started a new round. A continuous sequence of ♠ martingale bets can

    thus be partitioned into a sequence of independent rounds. Following is an analysis of

    the expected value ♠ of one round.

    Let q be the probability of losing (e.g. for American

    double-zero roulette, it is 20/38 for a bet ♠ on black or red). Let B be the amount of

    the initial bet. Let n be the finite number of ♠ bets the gambler can afford to lose.

    The

    probability that the gambler will lose all n bets is qn. When all ♠ bets lose, the total

    loss is

    ∑ i = 1 n B ⋅ 2 i − 1 = B ( 2 ♠ n − 1 ) {\displaystyle \sum _{i=1}^{n}B\cdot

    2^{i-1}=B(2^{n}-1)}

    The probability the gambler does not lose all n bets is 1 − ♠ qn. In

    all other cases, the gambler wins the initial bet (B.) Thus, the expected profit per

    round is

    ( 1 ♠ − q n ) ⋅ B − q n ⋅ B ( 2 n − 1 ) = B ( ♠ 1 − ( 2 q ) n ) {\displaystyle

    (1-q^{n})\cdot B-q^{n}\cdot B(2^{n}-1)=B(1-(2q)^{n})}

    Whenever q > 1/2, the expression

    1 − (2q)n ♠ < 0 for all n > 0. Thus, for all games where a gambler is more likely to lose

    than ♠ to win any given bet, that gambler is expected to lose money, on average, each

    round. Increasing the size of ♠ wager for each round per the martingale system only

    serves to increase the average loss.

    Suppose a gambler has a 63-unit ♠ gambling bankroll.

    The gambler might bet 1 unit on the first spin. On each loss, the bet is doubled. Thus,

    ♠ taking k as the number of preceding consecutive losses, the player will always bet 2k

    units.

    With a win on any ♠ given spin, the gambler will net 1 unit over the total amount

    wagered to that point. Once this win is ♠ achieved, the gambler restarts the system with

    a 1 unit bet.

    With losses on all of the first six spins, the ♠ gambler loses a total of

    63 units. This exhausts the bankroll and the martingale cannot be continued.

    In this

    example, the ♠ probability of losing the entire bankroll and being unable to continue the

    martingale is equal to the probability of 6 ♠ consecutive losses: (10/19)6 = 2.1256%. The

    probability of winning is equal to 1 minus the probability of losing 6 times: ♠ 1 −

    (10/19)6 = 97.8744%.

    The expected amount won is (1 × 0.978744) = 0.978744.

    The expected

    amount lost is (63 × ♠ 0.021256)= 1.339118.

    Thus, the total expected value for each

    application of the betting system is (0.978744 − 1.339118) = −0.360374 .

    In ♠ a unique

    circumstance, this strategy can make sense. Suppose the gambler possesses exactly 63

    units but desperately needs a total ♠ of 64. Assuming q > 1/2 (it is a real casino) and

    he may only place bets at even odds, ♠ his best strategy is bold play: at each spin, he

    should bet the smallest amount such that if he wins ♠ he reaches his target immediately,

    and if he does not have enough for this, he should simply bet everything. Eventually ♠ he

    either goes bust or reaches his target. This strategy gives him a probability of

    97.8744% of achieving the goal ♠ of winning one unit vs. a 2.1256% chance of losing all

    63 units, and that is the best probability possible ♠ in this circumstance.[2] However,

    bold play is not always the optimal strategy for having the biggest possible chance to

    increase ♠ an initial capital to some desired higher amount. If the gambler can bet

    arbitrarily small amounts at arbitrarily long odds ♠ (but still with the same expected

    loss of 10/19 of the stake at each bet), and can only place one ♠ bet at each spin, then

    there are strategies with above 98% chance of attaining his goal, and these use very

    ♠ timid play unless the gambler is close to losing all his capital, in which case he does

    switch to extremely ♠ bold play.[3]

    Alternative mathematical analysis [ edit ]

    The

    previous analysis calculates expected value, but we can ask another question: what is

    ♠ the chance that one can play a casino game using the martingale strategy, and avoid the

    losing streak long enough ♠ to double one's bankroll?

    As before, this depends on the

    likelihood of losing 6 roulette spins in a row assuming we ♠ are betting red/black or

    even/odd. Many gamblers believe that the chances of losing 6 in a row are remote, and

    ♠ that with a patient adherence to the strategy they will slowly increase their

    bankroll.

    In reality, the odds of a streak ♠ of 6 losses in a row are much higher than

    many people intuitively believe. Psychological studies have shown that since ♠ people

    know that the odds of losing 6 times in a row out of 6 plays are low, they incorrectly

    ♠ assume that in a longer string of plays the odds are also very low. In fact, while the

    chance of ♠ losing 6 times in a row in 6 plays is a relatively low 1.8% on a single-zero

    wheel, the probability ♠ of losing 6 times in a row (i.e. encountering a streak of 6

    losses) at some point during a string ♠ of 200 plays is approximately 84%. Even if the

    gambler can tolerate betting ~1,000 times their original bet, a streak ♠ of 10 losses in

    a row has an ~11% chance of occurring in a string of 200 plays. Such a ♠ loss streak

    would likely wipe out the bettor, as 10 consecutive losses using the martingale

    strategy means a loss of ♠ 1,023x the original bet.

    These unintuitively risky

    probabilities raise the bankroll requirement for "safe" long-term martingale betting to

    infeasibly high numbers. ♠ To have an under 10% chance of failing to survive a long loss

    streak during 5,000 plays, the bettor must ♠ have enough to double their bets for 15

    losses. This means the bettor must have over 65,500 (2^15-1 for their ♠ 15 losses and

    2^15 for their 16th streak-ending winning bet) times their original bet size. Thus, a

    player making 10 ♠ unit bets would want to have over 655,000 units in their bankroll (and

    still have a ~5.5% chance of losing ♠ it all during 5,000 plays).

    When people are asked

    to invent data representing 200 coin tosses, they often do not add ♠ streaks of more than

    5 because they believe that these streaks are very unlikely.[4] This intuitive belief

    is sometimes referred ♠ to as the representativeness heuristic.

    In a classic martingale

    betting style, gamblers increase bets after each loss in hopes that an ♠ eventual win

    will recover all previous losses. The anti-martingale approach, also known as the

    reverse martingale, instead increases bets after ♠ wins, while reducing them after a

    loss. The perception is that the gambler will benefit from a winning streak or ♠ a "hot

    hand", while reducing losses while "cold" or otherwise having a losing streak. As the

    single bets are independent ♠ from each other (and from the gambler's expectations), the

    concept of winning "streaks" is merely an example of gambler's fallacy, ♠ and the

    anti-martingale strategy fails to make any money.

    If on the other hand, real-life stock

    returns are serially correlated (for ♠ instance due to economic cycles and delayed

    reaction to news of larger market participants), "streaks" of wins or losses do ♠ happen

    more often and are longer than those under a purely random process, the anti-martingale

    strategy could theoretically apply and ♠ can be used in trading systems (as

    trend-following or "doubling up"). This concept is similar to that used in momentum

    ♠ investing and some technical analysis investing strategies.

    See also [ edit ]

    Double or

    nothing – A decision in gambling that will ♠ either double ones losses or cancel them

    out

    Escalation of commitment – A human behavior pattern in which the participant takes

    ♠ on increasingly greater risk

    St. Petersburg paradox – Paradox involving a game with

    repeated coin flipping

    Sunk cost fallacy – Cost that ♠ has already been incurred and

    cannot be recovered Pages displaying short descriptions of redirect targets

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