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mitzvahceremonies.com:2025/1/13 15:34:02
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A polícia holandesa deteve um homem no sábado depois que ele deixou uma boate onde quatro pessoas foram mantidas reféns 👍 por horas, trazendo o fim pacífico a seu tenso impasse.
"Estamos excepcionalmente felizes por ter terminado desta forma, que as vítimas 👍 saíram com segurança e conseguimos prender esse suspeito sem usar violência", disse Marthyne Kunst.
Não houve nenhuma palavra imediata sobre um 👍 motivo, mas a polícia e os promotores disseram que não acreditavam ter sido incidente terrorista. A Polícia disse o sequestrador 👍 estava armado com facas uma mochila ele carregava foi examinada para estabelecer se continha explosivos
A tomada de reféns na 👍 cidade holandesa central do mercado Ede, 85 quilômetros (53 milhas) a sudeste da Amsterdã. terminou por volta ao meio-dia quando 👍 um homem saiu fora o Cafe Petticoat clube e foi ordenado pela polícia armada para se ajoelhar com as mãos 👍 bwin espanabwin espanacabeça Ele então era algemado antes ser levado dentro uma viatura policial esperando
Kunst disse a repórteres que o 👍 homem era conhecido das autoridades policiais e já havia sido condenado por comportamento ameaçador. Ela não deu mais detalhes, citando 👍 privacidade ou investigação bwin espana andamento ”.
A identidade do suspeito não foi divulgada. O prefeito de Ede, René Verhulst disse que 👍 ele era um cidadão holandês
As autoridades também não divulgaram detalhes sobre os quatro reféns.
Verhulst disse que depois de uma manhã 👍 emocionalmente carregada, "tudo está bem. O sequestrador é preso pela polícia e agora eles estão falando com ele." E os 👍 reféns são livres? muito emocionais".
Mais cedo, três jovens reféns saíram do clube com as mãos acima da cabeça. Uma quarta 👍 pessoa foi libertada pouco antes de o suspeito ser preso e os sequestradores eram todos trabalhadores no local
Polícia fortemente armada 👍 e equipes de detenção especiais, algumas usando máscaras se reuniram fora do clube popular. Cerca das 150 casas próximas foram 👍 retiradas da cidade para que os trens não párassem na estação local ndia
28 de mar. de 2024
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A gambling strategy where the amount is raised until a person wins or becomes
insolvent
A martingale is a class of 🌝 betting strategies that originated from and were
popular in 18th-century France. The simplest of these strategies was designed for a
🌝 game in which the gambler wins the stake if a coin comes up heads and loses if it comes
up 🌝 tails. The strategy had the gambler double the bet after every loss, so that the
first win would recover all 🌝 previous losses plus win a profit equal to the original
stake. Thus the strategy is an instantiation of the St. 🌝 Petersburg paradox.
Since a
gambler will almost surely eventually flip heads, the martingale betting strategy is
certain to make money for 🌝 the gambler provided they have infinite wealth and there is
no limit on money earned in a single bet. However, 🌝 no gambler has infinite wealth, and
the exponential growth of the bets can bankrupt unlucky gamblers who choose to use 🌝 the
martingale, causing a catastrophic loss. Despite the fact that the gambler usually wins
a small net reward, thus appearing 🌝 to have a sound strategy, the gambler's expected
value remains zero because the small probability that the gambler will suffer 🌝 a
catastrophic loss exactly balances with the expected gain. In a casino, the expected
value is negative, due to the 🌝 house's edge. Additionally, as the likelihood of a string
of consecutive losses is higher than common intuition suggests, martingale strategies
🌝 can bankrupt a gambler quickly.
The martingale strategy has also been applied to
roulette, as the probability of hitting either red 🌝 or black is close to 50%.
Intuitive
analysis [ edit ]
The fundamental reason why all martingale-type betting systems fail
is that 🌝 no amount of information about the results of past bets can be used to predict
the results of a future 🌝 bet with accuracy better than chance. In mathematical
terminology, this corresponds to the assumption that the win–loss outcomes of each 🌝 bet
are independent and identically distributed random variables, an assumption which is
valid in many realistic situations. It follows from 🌝 this assumption that the expected
value of a series of bets is equal to the sum, over all bets that 🌝 could potentially
occur in the series, of the expected value of a potential bet times the probability
that the player 🌝 will make that bet. In most casino games, the expected value of any
individual bet is negative, so the sum 🌝 of many negative numbers will also always be
negative.
The martingale strategy fails even with unbounded stopping time, as long as
🌝 there is a limit on earnings or on the bets (which is also true in practice).[1] It is
only with 🌝 unbounded wealth, bets and time that it could be argued that the martingale
becomes a winning strategy.
Mathematical analysis [ edit 🌝 ]
The impossibility of winning
over the long run, given a limit of the size of bets or a limit in 🌝 the size of one's
bankroll or line of credit, is proven by the optional stopping theorem.[1]
However,
without these limits, the 🌝 martingale betting strategy is certain to make money for the
gambler because the chance of at least one coin flip 🌝 coming up heads approaches one as
the number of coin flips approaches infinity.
Mathematical analysis of a single round [
edit 🌝 ]
Let one round be defined as a sequence of consecutive losses followed by either
a win, or bankruptcy of the 🌝 gambler. After a win, the gambler "resets" and is
considered to have started a new round. A continuous sequence of 🌝 martingale bets can
thus be partitioned into a sequence of independent rounds. Following is an analysis of
the expected value 🌝 of one round.
Let q be the probability of losing (e.g. for American
double-zero roulette, it is 20/38 for a bet 🌝 on black or red). Let B be the amount of
the initial bet. Let n be the finite number of 🌝 bets the gambler can afford to lose.
The
probability that the gambler will lose all n bets is qn. When all 🌝 bets lose, the total
loss is
∑ i = 1 n B ⋅ 2 i − 1 = B ( 2 🌝 n − 1 ) {\displaystyle \sum _{i=1}^{n}B\cdot
2^{i-1}=B(2^{n}-1)}
The probability the gambler does not lose all n bets is 1 − 🌝 qn. In
all other cases, the gambler wins the initial bet (B.) Thus, the expected profit per
round is
( 1 🌝 − q n ) ⋅ B − q n ⋅ B ( 2 n − 1 ) = B ( 🌝 1 − ( 2 q ) n ) {\displaystyle
(1-q^{n})\cdot B-q^{n}\cdot B(2^{n}-1)=B(1-(2q)^{n})}
Whenever q > 1/2, the expression
1 − (2q)n 🌝 < 0 for all n > 0. Thus, for all games where a gambler is more likely to lose
than 🌝 to win any given bet, that gambler is expected to lose money, on average, each
round. Increasing the size of 🌝 wager for each round per the martingale system only
serves to increase the average loss.
Suppose a gambler has a 63-unit 🌝 gambling bankroll.
The gambler might bet 1 unit on the first spin. On each loss, the bet is doubled. Thus,
🌝 taking k as the number of preceding consecutive losses, the player will always bet 2k
units.
With a win on any 🌝 given spin, the gambler will net 1 unit over the total amount
wagered to that point. Once this win is 🌝 achieved, the gambler restarts the system with
a 1 unit bet.
With losses on all of the first six spins, the 🌝 gambler loses a total of
63 units. This exhausts the bankroll and the martingale cannot be continued.
In this
example, the 🌝 probability of losing the entire bankroll and being unable to continue the
martingale is equal to the probability of 6 🌝 consecutive losses: (10/19)6 = 2.1256%. The
probability of winning is equal to 1 minus the probability of losing 6 times: 🌝 1 −
(10/19)6 = 97.8744%.
The expected amount won is (1 × 0.978744) = 0.978744.
The expected
amount lost is (63 × 🌝 0.021256)= 1.339118.
Thus, the total expected value for each
application of the betting system is (0.978744 − 1.339118) = −0.360374 .
In 🌝 a unique
circumstance, this strategy can make sense. Suppose the gambler possesses exactly 63
units but desperately needs a total 🌝 of 64. Assuming q > 1/2 (it is a real casino) and
he may only place bets at even odds, 🌝 his best strategy is bold play: at each spin, he
should bet the smallest amount such that if he wins 🌝 he reaches his target immediately,
and if he does not have enough for this, he should simply bet everything. Eventually 🌝 he
either goes bust or reaches his target. This strategy gives him a probability of
97.8744% of achieving the goal 🌝 of winning one unit vs. a 2.1256% chance of losing all
63 units, and that is the best probability possible 🌝 in this circumstance.[2] However,
bold play is not always the optimal strategy for having the biggest possible chance to
increase 🌝 an initial capital to some desired higher amount. If the gambler can bet
arbitrarily small amounts at arbitrarily long odds 🌝 (but still with the same expected
loss of 10/19 of the stake at each bet), and can only place one 🌝 bet at each spin, then
there are strategies with above 98% chance of attaining his goal, and these use very
🌝 timid play unless the gambler is close to losing all his capital, in which case he does
switch to extremely 🌝 bold play.[3]
Alternative mathematical analysis [ edit ]
The
previous analysis calculates expected value, but we can ask another question: what is
🌝 the chance that one can play a casino game using the martingale strategy, and avoid the
losing streak long enough 🌝 to double one's bankroll?
As before, this depends on the
likelihood of losing 6 roulette spins in a row assuming we 🌝 are betting red/black or
even/odd. Many gamblers believe that the chances of losing 6 in a row are remote, and
🌝 that with a patient adherence to the strategy they will slowly increase their
bankroll.
In reality, the odds of a streak 🌝 of 6 losses in a row are much higher than
many people intuitively believe. Psychological studies have shown that since 🌝 people
know that the odds of losing 6 times in a row out of 6 plays are low, they incorrectly
🌝 assume that in a longer string of plays the odds are also very low. In fact, while the
chance of 🌝 losing 6 times in a row in 6 plays is a relatively low 1.8% on a single-zero
wheel, the probability 🌝 of losing 6 times in a row (i.e. encountering a streak of 6
losses) at some point during a string 🌝 of 200 plays is approximately 84%. Even if the
gambler can tolerate betting ~1,000 times their original bet, a streak 🌝 of 10 losses in
a row has an ~11% chance of occurring in a string of 200 plays. Such a 🌝 loss streak
would likely wipe out the bettor, as 10 consecutive losses using the martingale
strategy means a loss of 🌝 1,023x the original bet.
These unintuitively risky
probabilities raise the bankroll requirement for "safe" long-term martingale betting to
infeasibly high numbers. 🌝 To have an under 10% chance of failing to survive a long loss
streak during 5,000 plays, the bettor must 🌝 have enough to double their bets for 15
losses. This means the bettor must have over 65,500 (2^15-1 for their 🌝 15 losses and
2^15 for their 16th streak-ending winning bet) times their original bet size. Thus, a
player making 10 🌝 unit bets would want to have over 655,000 units in their bankroll (and
still have a ~5.5% chance of losing 🌝 it all during 5,000 plays).
When people are asked
to invent data representing 200 coin tosses, they often do not add 🌝 streaks of more than
5 because they believe that these streaks are very unlikely.[4] This intuitive belief
is sometimes referred 🌝 to as the representativeness heuristic.
In a classic martingale
betting style, gamblers increase bets after each loss in hopes that an 🌝 eventual win
will recover all previous losses. The anti-martingale approach, also known as the
reverse martingale, instead increases bets after 🌝 wins, while reducing them after a
loss. The perception is that the gambler will benefit from a winning streak or 🌝 a "hot
hand", while reducing losses while "cold" or otherwise having a losing streak. As the
single bets are independent 🌝 from each other (and from the gambler's expectations), the
concept of winning "streaks" is merely an example of gambler's fallacy, 🌝 and the
anti-martingale strategy fails to make any money.
If on the other hand, real-life stock
returns are serially correlated (for 🌝 instance due to economic cycles and delayed
reaction to news of larger market participants), "streaks" of wins or losses do 🌝 happen
more often and are longer than those under a purely random process, the anti-martingale
strategy could theoretically apply and 🌝 can be used in trading systems (as
trend-following or "doubling up"). This concept is similar to that used in momentum
🌝 investing and some technical analysis investing strategies.
See also [ edit ]
Double or
nothing – A decision in gambling that will 🌝 either double ones losses or cancel them
out
Escalation of commitment – A human behavior pattern in which the participant takes
🌝 on increasingly greater risk
St. Petersburg paradox – Paradox involving a game with
repeated coin flipping
Sunk cost fallacy – Cost that 🌝 has already been incurred and
cannot be recovered Pages displaying short descriptions of redirect targets
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2025/1/13 15:34:02